0.5x^2+2x+cos(x)=0

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Solution for 0.5x^2+2x+cos(x)=0 equation: 


Simplifying
0.5x2 + 2x + cos(x) = 0

Multiply cos * x
0.5x2 + 2x + cosx = 0

Reorder the terms:
cosx + 2x + 0.5x2 = 0

Solving
cosx + 2x + 0.5x2 = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2x' to each side of the equation.
cosx + 2x + -2x + 0.5x2 = 0 + -2x

Combine like terms: 2x + -2x = 0
cosx + 0 + 0.5x2 = 0 + -2x
cosx + 0.5x2 = 0 + -2x
Remove the zero:
cosx + 0.5x2 = -2x

Add '-0.5x2' to each side of the equation.
cosx + 0.5x2 + -0.5x2 = -2x + -0.5x2

Combine like terms: 0.5x2 + -0.5x2 = 0.0
cosx + 0.0 = -2x + -0.5x2
cosx = -2x + -0.5x2

Divide each side by 'osx'.
c = -2o-1s-1 + -0.5o-1s-1x

Simplifying
c = -2o-1s-1 + -0.5o-1s-1x

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